Zend Server should start up at IPL by default. This article describes how that happens, tells how to set up the autostart job entry if needed, and provides an alternate method using the Start Up Program (QSTRUPPGM system value) provided with the IBM i.
Zend Server 6, 7, or 8, running on any supported version of IBM i.
The Zend Server installation will create an autostart job entry in subsystem QSYSWRK. To verify this entry was created successfully, from a 5250 command line with a *SECOFR class profile:
Use option "3. Autostart job entries". Look for the "ZS_STR_SBS" entry (probably the last entry). It should look like this:
ZS_STR_SBS ZSVRIPLD ZENDSVR6
If the entry is missing, please add it:
ADDAJE SBSD(QSYSWRK) JOB(ZS_STR_SBS) JOBD(ZENDSVR6/ZSVRIPLD)
If the entry is there, but the ZENDSVR6 subsystem is not starting up correctly, there may be some timing issue. If this is the case, you can sometimes just put the commands to start the ZENDSVR6 subsystem in the start up program defined by the QSTRUPPGM system value.
To start Zend Server from the start up program you can use this SBMJOB command:
SBMJOB CMD(CALL PGM(ZENDSVR6/ZSTRSBS)) +
JOB(START_ZSV) JOBD(ZENDSVR6/ZSVR_JOBD) +
If you do this, please remove the autostart job entry from QSYSWRK, to prevent any partial start up of the subsystem.
RMVAJE SBSD(QSYSWRK) JOB(ZS_STR_SBS)
If the ZENDSVR6 subsystem is starting up OK, but the ZENDSVR6 Apache job is not starting in subsystem QHTTPSVR, you may leave the autostart job entry in QSYSWRK, and just use this command in your start up program to start Apache:
STRTCPSVR SERVER(*HTTP) HTTPSVR(ZENDSVR6)